1 solutions

  • 0
    @ 2024-4-19 17:59:22
    #include<iostream>
    #include<string>
    using namespace std;
    int n;
    int main()
    {
        cin>>n;
        char a[1003][1003];
        string b;
        cin.get();//读取回车;
        getline(cin,b);//读取带空格的字符串
      
        int lenth  = b.length();
        int hang = lenth/n;
        if(lenth%n)hang++;
      
        int p = 0;
        for(int j = hang-1;j>=0;j--)
        {
            for(int i = 0;i < n;i++){
                if(b[p])a[i][j] = b[p];
                else a[i][j] = ' ';
                p++;
            }
        }
        for(int i = 0;i < n;i++)
        {
            for(int j = 0;j < hang;j++)
            {
                cout<<a[i][j];
            }
            puts("");
        }
        return 0;
    }
    
    • 1

    Information

    ID
    211
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    9
    Tags
    # Submissions
    44
    Accepted
    5
    Uploaded By