1 solutions

  • 0
    @ 2024-4-10 20:24:07
    #include<iostream>
    using namespace std;
    int main()
    {   int t;
        int s[105],n[105];
        cin>>t;
        int sum = 0;
        for(int i = 1;i <= t;i++)
        {
          cin>>s[i]>>n[i];
          int u = s[i];
         if(n[i]) for(int j = 1;j <= n[i];j++)u= u*95/100;
          int r = s[i]*7/10;
          sum += max(u,r);
        }
        printf("%d",sum);
        return 0;
    }
    
    • 1

    Information

    ID
    6962
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    8
    Tags
    # Submissions
    74
    Accepted
    14
    Uploaded By