3 solutions

  • 0
    @ 2022-11-26 18:16:54
    #include<iostream>
    #include<iomanip>  // --->setprecision所需头文件
    using namespace std;
    
    int main(){
    	int T, n;
    	double ans;
    	cin >> T;
    	for(int i = 1; i <= T; i++){
    		cin >> n;
    		
    		if(n < 60)
    			cout << "0.0" << endl;
    		else{
    			ans = 1.0 * (n - 60) / 10 + 1;
    			cout << setprecision(1) << fixed<< ans << endl;	//保留一位小数
    		}		
    	}
    	
    	return 0;
    }
    

    Information

    ID
    23
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    7
    Tags
    # Submissions
    775
    Accepted
    196
    Uploaded By